自己写了一个头文件LCD.H,在其间界说了如下的全局变量:
const int8 NoCheckBusy = 0;
const int8 CheckBusy = 1;
const int32 LCD_RS = 1<<4;
const int32 LCD_RW = 1<<5;
const int32 LCD_EN = 1<<6;
const int32 LCD_DATA = 0xff<<7;
在c文件lcd.c和main.c中都要用到,但是在编译的时分呈现如下的问题:
Error: L6200E: Symbol NoCheckBusy multiply defined (by main.o and lcd.o).
Error: L6200E: Symbol LCD_RS multiply defined (by main.o and lcd.o).
上网站arm.com/help/index.jsp?topic=/com.arm.doc.dui0435a/index.html” target=”_blank”>http://infocenter.arm.com/help/index.jsp?topic=/com.arm.doc.dui0435a/index.html上去查找,有如下成果:
L6200E:
There are two common examples where this occurs:
This error is reported when functions that use semihosting SWIs are linked in from the C library, in the presence of the
To resolve this, you must provide your own implementations of these C library functions.
The ADS 1.2 Examplesembedded directory contains examples of how to re-implement some of the more common SWI-using functions – see the file
To identify which SWI-using functions are being linked-in from the C libraries:
1. Link with armlink -verbose -errors err.txt
2. Search err.txt for occurrences of __I_use_semihosting_swi
For example:
:
Loading member sys_exit.o from c_a__un.l.
:
This shows that the SWI-using function _sys_exit is being linked-in from the C library.
This means that there are two conflicting definitions of
stdio.o
To identify why stdio.o is being linked-in, you must link with the linkers “verbose” switch, e.g.:
Then study
To move forward, the user may have to either:
– Eliminate the calls like
– Re-implement the
详细是什么意思看的也不是很懂,后来看了他人的处理方法是:在头文件中仅声明变量,而把变量的界说都放到c文件中去,问题就处理了。
即把
const int8 NoCheckBusy = 0;
const int8 CheckBusy = 1;
const int32 LCD_RS = 1<<4;
const int32 LCD_RW = 1<<5;
const int32 LCD_EN = 1<<6;
const int32 LCD_DATA = 0xff<<7;
都放到lcd.c中就可防止该问题,时刻不多,详细原因还有待研讨。