判别回文
int isReverseStr(char * aStr)
int i,j;
int found=1;
if(aSTR==null)
return -1;
j=strlen(aStr);
for (i=0;i
if (*(aStr+i)!=*(aStr+j-i-1)){//假设不相等
found=0;
break;
}
return found;
}
//去除后边的零，并给出除零外的长度 可以用打印函数调用
unsigned char zwwlen(unsigned char *buf,unsigned char len)
{
char i;
for (i=(len-1);i>=0;i–)
{
if (buf[i]!= 0)
break;
}
if (i<0)//如果是0输出1个0
{
i=0;
}
return (i+1);
}
//依据上题
void print( unsigned char *buf,unsigned char len )
{
for( ; len > 0 ; len — )
{
SBUF = *buf ;
while( !TI )
{
;
}
TI = 0 ;
buf ++ ;
}
ES = 1 ;
}
//把数字转成16制止
for (i = 0;i<10;i++)
{
string[i*2] = IdInfo.workernum[i]>>4;
string[i*2 +1] =IdInfo.workernum[i] & 0x0f;
}
//处理string[i] 的内容放到string[j]中
for (i=0,j=0;i<20;i++)
{
if (string[i] == 0x0B)
{
break; //B完毕
}
else if(string[i] <0x0A)//是数字
{
string[j++] = string[i] + 0;
}
else if (string[i] > 0x0B)
{
string[j++] = ((string[i]<<4)|string[i+1])&0x7F;
}
}
string[j] = ;//完毕符
//string[j] 里边的内容便是A 开端
//这儿打印的是string[j]的内容所以处理了A 开端B完毕
print( string , 10 );
//依据形式挑选消费金额
//消费金额
switch ( *(buffdata+1) )
{
case SM_REC_CON_MIX: //混合消费记载
//取出补助消费
buse = *(buffdata+11) ;
buse = (buse<<8) | *(buffdata+12) ;
buse = (buse<<8) | *(buffdata+13) ;
//取出主钱包消费金额
TempNumber = *(buffdata+18) ;
TempNumber = (TempNumber<<8) | *(buffdata+19) ;
TempNumber = (TempNumber<<8) | *(buffdata+20) ;
//核算总的消费金额
TempNumber += buse ;
break ;
default: //主钱包消费记载, 补助钱包消费记载
TempNumber = (* ( ulong * ) (buffdata+18))>>8 ;
break;
}
print( pconsum , 10 ) ;
print(string,sprintf( string, “%lu”,TempNumber/100 ));
print(pdian, 1) ;
sprintf( string, “%8.3lu”,TempNumber );
print( string+6 , 2 ) ;
// print( pyuan , 2 ) ;
print(“x0Dx0A”,2); //打印机指令
